Senin, 22 Oktober 2012

UJIAN ONLINE AS4 : Soal Nomor 2

KETENTUAN UJIAN ONLINE AS4 :
1.  Peserta kuliah wajib mengikuti dan menjawab soal ujian online pada www.strukturbeton1.blogspot.com
2.  Dikerjakan menggunakan metode matriks kekakuan langsung (program frame2d; truss2d)
3.  Jawaban lengkap disampaikan melalui email : strukturbeton@gmail.com dan sumirinms@gmail.com
4.  Jawaban ringkas dituliskan pada komentar tiap2 halaman soal dalam blog ini.
5.  Jawaban dinilai pada proses, makin cepat menjawab makin baik nilainya. Jawaban boleh diperbaiki lagi, dikirim ulang, paling lambat tgl 27 Oktober 2012 jam 24.00 WIB.

Jawablah ringkas (lewat komentar, yg cepat dan benar nilainya 100 tiap soal) :
         (a)Reaksi Ry  pada titik 1,2,3,4,5,6,7  
Jawablah lengkap (lewat email, yang tidak diminta tidak usah dikirim);
         (a)Input data;  (b)cek kesetimbangan Sigma FX, Sigma FY; (c)Free body diagram;
         (d)Buktikan Gambar Bidang M, D, N tergambar di atas adalah benar !.
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13 komentar:

  1. Unknown25 Oktober 2012 pukul 20.24

    Komentar ini telah dihapus oleh pengarang.

    BalasHapus
  2. Unknown25 Oktober 2012 pukul 20.58

    Nama : Danu Agus S
    Nim : 022103046

    Batang 1:
    Ry ditik 1 = Rya
    = (1/2 x q1 x L)
    = (1/2 x 2 x 6)
    = 6 ton

    Ry ditik 2 = Rby
    = (0.5 x q1 x L)
    = (0.5 x 2 x 8)
    = 6 ton


    Batang 2:
    Ry ditik 2 = Rya
    = Ry = P
    = 8 ton

    Ry ditik 3 = Rby
    = Ry = P
    = 8 ton

    Batang 3:

    Ry ditik 3 = Rya
    = (0.5xP)
    = (0.5x12)
    = 6 ton

    Ry ditik 4= Rby
    = (0.5xP)
    = (0.5x12)
    = 6 ton

    Batang 4:

    Ry ditik 4 = Rya
    = (0.5 x (q x L/2))
    = (0.5 x (6 x 6/2))
    = 9 ton

    Ry ditik 5= Rby
    = (0.5 x (q x L/2))
    = (0.5 x (6 x 6/2))
    = 9 ton

    Batang 5:

    Ry ditik 5 = Rya
    = -(3/10 x (q x L/2))
    = -(3/10 x (6 x 6/2))
    = -5,4 ton

    Ry ditik 6= Rby
    = -(3/10 x (q x L/2))
    = -(3/10 x (6 x 6/2))
    = -5,4 ton

    Batang 6:

    Ry ditik 6= Rya
    = (3/10 x (q x L/2))
    = (3/10 x (6 x 6/2))
    = 5,4 ton

    Ry ditik 7= Rby
    = (3/10 x (q x L/2))
    = (3/10 x (6 x 6/2))
    = 5,4 ton

    BalasHapus
  3. Unknown25 Oktober 2012 pukul 22.13

    Komentar ini telah dihapus oleh pengarang.

    BalasHapus
  4. Unknown26 Oktober 2012 pukul 02.05

    Nama : Andrean Rizal Saputra
    Nim : 022103039


    Ry ditik 1 = Rya batang 1
    = (1/2 x q1 x L)
    = (1/2 x 2 x 6)
    = 6 ton

    Ry ditik 2 = Rby batang 1 + ray batang 2
    = (0.5 x q1 x L) + (( (p x bc) / L) + ((p x c ) / L)
    = (0.5 x 2 x 8) + (((9 x 4,5) / 6) + ((9 x 1,5) / 6)
    = 6 + 9
    = 15 ton

    Ry ditik 3 = Rby batang 2 + ray batang 3
    = (( (p x ab) / L) + ((p x a ) / L) + (1/2 P)
    = (((9 x 4,5) / 6) + ((9 x 1,5) / 6) + (1/2 x 12)
    = 9 + 6
    = 15 ton

    Ry ditik 4 = Rby batang 3 + ray batang 4
    = (1/2P) + (1/4 x q x L)
    = (1/2 x 12) + (1/4 x 6 x 6)
    = 6 + 9
    = 15 ton

    Ry ditik 5 = Rby batang 4 + ray batang 5
    = (1/4 x q x L) + ( 7/20 x q x L )
    = (1/4 x 6 x 6) + ( 7/20 x 6 x 6 )
    = 9 + 12,6
    = 21,6 ton

    Ry ditik 6 = Rby batang 5 + ray batang 6
    = ( 3/20 x q x L ) + ( 3/20 x q x L )
    = ( 3/20 x 6 x 6 ) + ( 3/20 x 6 x 6 )
    = 5,4 + 5,4
    = 8,8 ton


    Ry ditik 7 = Rby batang 6
    = ( 7/20 x q x L )
    = ( 7/20 x 6 x 6 )
    = 12,6 t

    BalasHapus
  5. Unknown26 Oktober 2012 pukul 04.33

    NAMA : AGUS KRISNANTO
    NIM : 022103036


    RY DITIK 1 = RYA BATANG 1
    = (1/2 x q1 x L)
    = (1/2 x 2 x 6)
    = 6 t
    RY DITIK 2 = RBY BATANG 1 + RAY BATANG 2
    = (0.5 x q1 x L) + (( (p x bc) / L) + ((p x c ) / L)
    = (0.5 x 2 x 8) + (((9 x 4,5) / 6) + ((9 x 1,5) / 6)
    = 15 t
    RY DITIK 3 = RBY BATANG 2 + RAY BATANG 3
    = (( (p x ab) / L) + ((p x a ) / L) + (1/2 P)
    = (((9 x 4,5) / 6) + ((9 x 1,5) / 6) + (1/2 x 12)
    = 15 t
    RY DITIK 4 = RBY BATANG 3 + RAY BATANG 4
    = (1/2P) + (1/4 x q x L)
    = (1/2 x 12) + (1/4 x 6 x 6)
    = 15 t
    RY DITIK 5 = RBY BATANG 4 + RAY BATANG 5
    = (1/4 x q x L) + ( 7/20 x q x L )
    = (1/4 x 6 x 6) + ( 7/20 x 6 x 6 )
    = 21,6 t
    RY DITIK 6 = RBY BATANG 5 + RAY BATANG 6
    = ( 3/20 x q x L ) + ( 3/20 x q x L )
    = ( 3/20 x 6 x 6 ) + ( 3/20 x 6 x 6 )
    = 8,8 t
    RY DITIK 7 = RBY BATANG 6
    = ( 7/20 x q x L )
    = ( 7/20 x 6 x 6 )
    = 12,6 t

    BalasHapus
  6. Unknown26 Oktober 2012 pukul 06.30

    Nama : Pandu Aji Jatinofa
    Nim : 022103070
    q1 = 2 t/m
    q2 = 6 t/m
    q3 = 6 t/m
    q4 = 6 t/m

    Ry Titik 1 = RA Elment 1
    = 0,5 x q1 x L
    = 0,5 x 2 x 6
    = 6 ton

    Ry Titik 2 = RB batang 1 + RA batang 2
    = (0,5 x q1 x L) + P
    = (0,5 x 2 x 6) + 9
    = 6 + 9
    = 15 ton
    Ry Titik 3 = RB batang 2 + RA batang 3
    = P + (0,5 x P)
    = 9 + (0,5 x 12)
    = 9 + 6
    = 15 ton
    Ry Titik 4 = RB batang 3 + RA batang 4
    = (0,5 x P) + (0.25 x q2 x L)
    = (0,5 x 12) + (0.25 x 6 x 6)
    = 6 + 9
    = 15 ton
    Ry Titik 5 = RB batang 4 + RA batang 5
    = (0,25 x q2 x L) + ( 7/20 x q3 x L )
    = (0,25 x 6 x 6) + ( 7/20 x 6 x 6 )
    = 9 + 12,6
    = 21,6 ton
    Ry Titik 6 = RB batang 5 + RA batang 6
    = ( 3/20 x q3 x L ) + ( 3/20 x q4 x L )
    = ( 3/20 x 6 x 6 ) + ( 3/20 x 6 x 6 )
    = 5,4 + 5,4
    = 10,8 ton
    Ry ditik 7 = Rby batang 6
    = ( 7/20 x q4 x L )
    = ( 7/20 x 6 x 6 )
    = 12,6 ton

    BalasHapus
  7. Unknown26 Oktober 2012 pukul 09.02

    Nama :M.Syaifudin_022103059
    Ry dititik 1=Ra batang kiri
    Ra=1/2*q*l
    =1/2*2*6
    =6t
    Ry dititik 2=Rb1 batang kanan+Ra2 batang kiri
    Rb1+Ra2=(1/2*q*l) +{ (p1*b^2/l^3)*(3*a1+b)+ (p1*b^2/l^3)*(3*a2+b)}
    =(1/2*2*6)+{ (8*4.5^2/6^3)*(3*1.5+4.5)+ (8*1.5^2/6^3)*(3*4.5+1.5)}
    =(6t)+{(6.75)+(1.25)}
    =14t
    Ry dititik 3=Ra2 batang kanan + Ra3 batang kiri
    Rb2+Ra3={ (p1*b^2/l^3)*(3*a1+b)+ (p1*b^2/l^3)*(3*a2+b)}+(1/2*p)
    ={(8)} + (1/2*12)
    = 8 + 6
    = 14t
    Ry dititik 4=Rb3 batang kanan + Ra4 batang kiri
    Rb3+Ra4= (1/2*p)+(1/4*q*l)
    =(1/2*12)+(1/4*6*6)
    = (6)+(9)
    = 15t
    Ry dititik 5=Rb4 batang kanan + Ra5 batang kiri
    Rb4+Ra5= (1/4*q*l) + (7/20*q*l)
    =(1/4*6*6) + (7/20*6*6)
    =( 9)+ (12,6)
    =21.6t
    Ry dititik 6=Rb5 batang kanan + Ra6 batang kiri
    Rb5+Ra6= (3/20*q*l) + (3/20*q*l)
    = (3/20*6*6) + (3/20*6*6)
    = (5.4) + (5.4)
    =10.8t
    Ry dititik 7=Rb6 batang kanan
    Rb6=(7/20*q*l)
    = (7/20*6*6)
    = 12,6t

    BalasHapus
  8. Unknown26 Oktober 2012 pukul 17.04

    Danu Agus S
    022103046

    Batang 1:
    Ry ditik 1 = Rya
    = (1/2 x q1 x L)
    = (1/2 x 2 x 6)
    = 6 ton

    Ry ditik 2 = Rby
    = (0.5 x q1 x L)
    = (0.5 x 2 x 8)
    = 6 ton


    Batang 2:
    Ry ditik 2 = Rya
    = Ry = P
    = 8 ton

    Ry ditik 3 = Rby
    = Ry = P
    = 8 ton

    Batang 3:

    Ry ditik 3 = Rya
    = (0.5xP)
    = (0.5x12)
    = 6 ton

    Ry ditik 4= Rby
    = (0.5xP)
    = (0.5x12)
    = 6 ton

    Batang 4:

    Ry ditik 4 = Rya
    = (0.5 x (q x L/2))
    = (0.5 x (6 x 6/2))
    =9 ton

    Ry ditik 5= Rby
    = (0.5 x (q x L/2))
    = (0.5 x (6 x 6/2))
    =9 ton

    Batang 5:

    Ry ditik 5 = Rya
    = -(3/10 x (q x L/2))
    = -(3/10 x (6 x 6/2))
    = -5,4 ton

    Ry ditik 6= Rby
    = -(7/10 x (q x L/2))
    = -(7/10 x (6 x 6/2))
    = -12,6 ton

    Batang 6:

    Ry ditik 6= Rya
    = (3/10 x (q x L/2))
    = (3/10 x (6 x 6/2))
    = 5,4 ton

    Ry ditik 7= Rby
    = (7/10 x (q x L/2))
    = (7/10 x (6 x 6/2))
    = 12,6 ton

    BalasHapus
  9. Unknown27 Oktober 2012 pukul 05.02

    Nama : tohir ibnush sholah
    Nim : 022103082


    Ry ditik 1 = Rya batang 1
    = (1/2 x q1 x L)
    = (1/2 x 2 x 6)
    = 6 ton

    Ry ditik 2 = Rby batang 1 + ray batang 2
    = (0.5 x q1 x L) + (( (p x bc) / L) + ((p x c ) / L)
    = (0.5 x 2 x 8) + (((9 x 4,5) / 6) + ((9 x 1,5) / 6)
    = 6 + 9
    = 15 ton

    Ry ditik 3 = Rby batang 2 + ray batang 3
    = (( (p x ab) / L) + ((p x a ) / L) + (1/2 P)
    = (((9 x 4,5) / 6) + ((9 x 1,5) / 6) + (1/2 x 12)
    = 9 + 6
    = 15 ton

    Ry ditik 4 = Rby batang 3 + ray batang 4
    = (1/2P) + (1/4 x q x L)
    = (1/2 x 12) + (1/4 x 6 x 6)
    = 6 + 9
    = 15 ton

    Ry ditik 5 = Rby batang 4 + ray batang 5
    = (1/4 x q x L) + ( 7/20 x q x L )
    = (1/4 x 6 x 6) + ( 7/20 x 6 x 6 )
    = 9 + 12,6
    = 21,6 ton

    Ry ditik 6 = Rby batang 5 + ray batang 6
    = ( 3/20 x q x L ) + ( 3/20 x q x L )
    = ( 3/20 x 6 x 6 ) + ( 3/20 x 6 x 6 )
    = 5,4 + 5,4
    = 8,8 ton


    Ry ditik 7 = Rby batang 6
    = ( 7/20 x q x L )
    = ( 7/20 x 6 x 6 )
    = 12,6 t

    BalasHapus
  10. Unknown27 Oktober 2012 pukul 05.17

    NAMA : Oky Fauzi Raharjo
    NIM : 022103069


    RY DITIK 1 = RYA BATANG 1
    = (1/2 x q1 x L)
    = (1/2 x 2 x 6)
    = 6 t
    RY DITIK 2 = RBY BATANG 1 + RAY BATANG 2
    = (0.5 x q1 x L) + (( (p x bc) / L) + ((p x c ) / L)
    = (0.5 x 2 x 8) + (((9 x 4,5) / 6) + ((9 x 1,5) / 6)
    = 15 t
    RY DITIK 3 = RBY BATANG 2 + RAY BATANG 3
    = (( (p x ab) / L) + ((p x a ) / L) + (1/2 P)
    = (((9 x 4,5) / 6) + ((9 x 1,5) / 6) + (1/2 x 12)
    = 15 t
    RY DITIK 4 = RBY BATANG 3 + RAY BATANG 4
    = (1/2P) + (1/4 x q x L)
    = (1/2 x 12) + (1/4 x 6 x 6)
    = 15 t
    RY DITIK 5 = RBY BATANG 4 + RAY BATANG 5
    = (1/4 x q x L) + ( 7/20 x q x L )
    = (1/4 x 6 x 6) + ( 7/20 x 6 x 6 )
    = 21,6 t
    RY DITIK 6 = RBY BATANG 5 + RAY BATANG 6
    = ( 3/20 x q x L ) + ( 3/20 x q x L )
    = ( 3/20 x 6 x 6 ) + ( 3/20 x 6 x 6 )
    = 8,8 t
    RY DITIK 7 = RBY BATANG 6
    = ( 7/20 x q x L )
    = ( 7/20 x 6 x 6 )
    = 12,6 t

    BalasHapus
  11. Unknown27 Oktober 2012 pukul 06.05

    Nama : Reija Bayu Admaja
    Nim : 022103072

    q1 = 2 t/m
    q2 = 6 t/m
    q3 = 6 t/m
    q4 = 6 t/m

    Ry Titik 1 = RA Elment 1
    = 0,5 x q1 x L
    = 0,5 x 2 x 6
    = 6 ton

    Ry Titik 2 = RB batang 1 + RA batang 2
    = (0,5 x q1 x L) + P
    = (0,5 x 2 x 6) + 9
    = 6 + 9
    = 15 ton

    Ry Titik 3 = RB batang 2 + RA batang 3
    = P + (0,5 x P)
    = 9 + (0,5 x 12)
    = 9 + 6
    = 15 ton

    Ry Titik 4 = RB batang 3 + RA batang 4
    = (0,5 x P) + (0.25 x q2 x L)
    = (0,5 x 12) + (0.25 x 6 x 6)
    = 6 + 9
    = 15 ton

    Ry Titik 5 = RB batang 4 + RA batang 5
    = (0,25 x q2 x L) + ( 7/20 x q3 x L )
    = (0,25 x 6 x 6) + ( 7/20 x 6 x 6 )
    = 9 + 12,6
    = 21,6 ton

    Ry Titik 6 = RB batang 5 + RA batang 6
    = ( 3/20 x q3 x L ) + ( 3/20 x q4 x L )
    = ( 3/20 x 6 x 6 ) + ( 3/20 x 6 x 6 )
    = 5,4 + 5,4
    = 10,8 ton

    Ry ditik 7 = Rby batang 6
    = ( 7/20 x q4 x L )
    = ( 7/20 x 6 x 6 )
    = 12,6 ton

    BalasHapus
  12. Unknown27 Oktober 2012 pukul 08.02

    Nama : galih satrio c
    NIM : 022103053
    Ry ditik 1 = Rya batang 1
    = (1/2 x q1 x L)
    = (1/2 x 2 x 6)
    = 6 ton

    Ry ditik 2 = Rby batang 1 + ray batang 2
    = (0.5 x q1 x L) + (( (p x bc) / L) + ((p x c ) / L)
    = (0.5 x 2 x 8) + (((9 x 4,5) / 6) + ((9 x 1,5) / 6)
    = 6 + 9
    = 15 ton

    Ry ditik 3 = Rby batang 2 + ray batang 3
    = (( (p x ab) / L) + ((p x a ) / L) + (1/2 P)
    = (((9 x 4,5) / 6) + ((9 x 1,5) / 6) + (1/2 x 12)
    = 9 + 6
    = 15 ton

    Ry ditik 4 = Rby batang 3 + ray batang 4
    = (1/2P) + (1/4 x q x L)
    = (1/2 x 12) + (1/4 x 6 x 6)
    = 6 + 9
    = 15 ton

    Ry ditik 5 = Rby batang 4 + ray batang 5
    = (1/4 x q x L) + ( 7/20 x q x L )
    = (1/4 x 6 x 6) + ( 7/20 x 6 x 6 )
    = 9 + 12,6
    = 21,6 ton

    Ry ditik 6 = Rby batang 5 + ray batang 6
    = ( 3/20 x q x L ) + ( 3/20 x q x L )
    = ( 3/20 x 6 x 6 ) + ( 3/20 x 6 x 6 )
    = 5,4 + 5,4
    = 8,8 ton


    Ry ditik 7 = Rby batang 6
    = ( 7/20 x q x L )
    = ( 7/20 x 6 x 6 )
    = 12,6 t

    BalasHapus
  13. Unknown27 Oktober 2012 pukul 09.43

     Reaksi Ry pada titik 1,2,3,4,5,6,7:
    Ry ditik 1 = Rya batang 1
    = (1/2 x q1 x L)
    = (1/2 x 2 x 6)
    = 6 ton

    Ry ditik 2 = Rby batang 1 + Ray batang 2
    = (0.5 x q1 x L) + (( (p x bc) / L) + ((p x c ) / L)
    = (0.5 x 2 x 8) + (((9 x 4,5) / 6) + ((9 x 1,5) / 6)
    = 6 + 9
    = 15 ton

    Ry ditik 3 = Rby batang 2 + Ray batang 3
    = (( (p x ab) / L) + ((p x a ) / L) + (1/2 P)
    = (((9 x 4,5) / 6) + ((9 x 1,5) / 6) + (1/2 x 12)
    = 9 + 6
    = 15 ton

    Ry ditik 4 = Rby batang 3 + Ray batang 4
    = (1/2P) + (1/4 x q x L)
    = (1/2 x 12) + (1/4 x 6 x 6)
    = 6 + 9
    = 15 ton

    Ry ditik 5 = Rby batang 4 + Ray batang 5
    = (1/4 x q x L) + ( 7/20 x q x L )
    = (1/4 x 6 x 6) + ( 7/20 x 6 x 6 )
    = 9 + 12,6
    = 21,6 ton

    Ry ditik 6 = Rby batang 5 + Ray batang 6
    = ( 3/20 x q x L ) + ( 3/20 x q x L )
    = ( 3/20 x 6 x 6 ) + ( 3/20 x 6 x 6 )
    = 5,4 + 5,4
    = 8,8 ton


    Ry ditik 7 = Rby batang 6
    = ( 7/20 x q x L )
    = ( 7/20 x 6 x 6 )
    = 12,6 t

    BalasHapus

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